










• 
The point
halfway between the two Gaussians should



cost –log(p(x))
bits where p(x) is its density under one of


the Gaussians.



– 
But
in the MDL story the cost should be –log(p(x))



plus
one bit to say which Gaussian we are using.



– 
How
can we make the MDL story give the right



answer?

