#include <iostream>
using std::cout;
using std::cin;

const int maxn = 1000;

int n, m;
//A[i][j] is the number at square (i, j). C arrays are 0 based hence the extra size.
int A[maxn+1][maxn+1];

int main() {
  cin >> n >> m;
  for(int i=1;i<=n;i++)
    for(int j=1;j<=m;j++)
      cin >> A[i][j];

  cout << A[1][1] + A[n][m] + 12 << '\n';
}